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Q: What two consecutive integers equal 71?

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71+72=143

There is no set of three consecutive integers whose sum is 71.

The equation would be 35+36=71.

35 and 36

The integers are 67, 69 and 71.

Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

* 71 * 73 * 75

They are 8 and 9

219/3 = 73 so the three are 73-2 = 71, 73 and 73+2 = 75.

In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).

71

Let the first integer be x. then x + (x+1) + (x+2) + (x+3) = 290 4x + 6 = 290 4x = 284 x = 71 so the nanswer is 71+72+73+74 = 290

71

There are no two consecutive integers that add up to 72. You can prove it this way: Let our numbers be represented by the variables "a" and "b". We are told: a = b + 1 a + b = 72 So we can use substitution to solve for either variable: (b + 1) + b = 72 2b + 1 = 72 2b = 71 b = 35.5 But 35.5 is not an integer, so this condition can not be met.

They are: 71+(-24) = 47

71 is equal to a prime number because it has only two factors which are itself and one.

71 is a single number and so there is no "between" possible!

647

The complex conjugate pair 2.5 - i*0.5*sqrt(71) and 2.5 + i*0.5*sqrt(71) where i is the imaginary number representing the square root of -1.

-71

There is only one mixed number equal to 7.5 . It is 71/2 .

There are 0.3048 metres in one foot. Therefore, rounded to two decimal places, 71 metres is equal to 71/0.3048 = 232.94 feet.

There are 2.54 centimetres in one inch. Therefore, rounded to two decimal places, 71 centimetres is equal to 71/2.54 = 27.95 inches.

71 x 71 = 5041

71*71 which is 5041